(w-3)[(w+2)(w+1)]=0

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Solution for (w-3)[(w+2)(w+1)]=0 equation:


Simplifying
(w + -3)[(w + 2)(w + 1)] = 0

Reorder the terms:
(-3 + w)[(w + 2)(w + 1)] = 0

Reorder the terms:
(-3 + w)[(2 + w)(w + 1)] = 0

Reorder the terms:
(-3 + w)[(2 + w)(1 + w)] = 0

Multiply (2 + w) * (1 + w)
(-3 + w)[(2(1 + w) + w(1 + w))] = 0
(-3 + w)[((1 * 2 + w * 2) + w(1 + w))] = 0
(-3 + w)[((2 + 2w) + w(1 + w))] = 0
(-3 + w)[(2 + 2w + (1 * w + w * w))] = 0
(-3 + w)[(2 + 2w + (1w + w2))] = 0

Combine like terms: 2w + 1w = 3w
(-3 + w)[(2 + 3w + w2)] = 0

Multiply (-3 + w) * [2 + 3w + w2]
(-3[2 + 3w + w2] + w[2 + 3w + w2]) = 0
([2 * -3 + 3w * -3 + w2 * -3] + w[2 + 3w + w2]) = 0
([-6 + -9w + -3w2] + w[2 + 3w + w2]) = 0
(-6 + -9w + -3w2 + [2 * w + 3w * w + w2 * w]) = 0
(-6 + -9w + -3w2 + [2w + 3w2 + w3]) = 0

Reorder the terms:
(-6 + -9w + 2w + -3w2 + 3w2 + w3) = 0

Combine like terms: -9w + 2w = -7w
(-6 + -7w + -3w2 + 3w2 + w3) = 0

Combine like terms: -3w2 + 3w2 = 0
(-6 + -7w + 0 + w3) = 0
(-6 + -7w + w3) = 0

Solving
-6 + -7w + w3 = 0

Solving for variable 'w'.

The solution to this equation could not be determined.

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